CS101 Final Term Solved Papers by Moaaz

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CS101 Final Term Solved Papers by Moaaz
CS101 Final Term Solved Papers by Moaaz
  • In the case of “(A+B)*C”, the closing parenthesis means that a “+” needs to be done.
    First. After sending A and B to postfix, we can do the addition
  • for the presence of parentheses. Then C will be sent to the postfix expression. Will be
  • followed by multiplication C and the result A + B. Postfix form
  • this expression is AB+C*. Sometimes we have two operators and need to make a
  • decision which to use first, as in this case “+” and “*”. In this case we have to see which

CS101 Final Term Solved Papers by Moaaz

  • operator has higher priority. Suppose we have a function “prcd(op1,op2)”
  • where op1 and op2 are two operators. The function “prcd(op1,op2)” returns TRUE
  • if op1 takes precedence over op2, otherwise FASLE. Suppose we call this function using
    arguments “*” and “+”, i.e. prcd(*, +), return true. The truth in will also return
  • case both op1 and op2 are “+”, e.g. if we have A+B+C, it doesn’t matter which +

CS101 Final Term Solved Papers by Moaaz

  • we perform first. Calling prcd(+, *) returns false because the priority of * is higher
  • than the + operator. The “+” must wait until the * is executed.
  • Now we will try to create an algorithm for converting the infix form to the postfix form. For this
    pseudocode will be written. We also write loops and if conditions.
  • Pseudocode is language independent. In this we will use stack
    algorithm. Here is the infix expression in string form. The algorithm is like
  • follows:
    Stack

CS101 Final Term Solved Papers by Moaaz