PHY101 Short Notes for Final Term and Mid Term .Aslam u alaikum dear students. If you are looking for Important PHY101 Short Notes for Final Term and Mid Term Then you are visiting the right website. I provided the perfect solution here according to my efforts. If there is any mistake then please correct it to get good grades in your Midterm and Final Term exams. Please verify the answers of all questions before remembering them for your Midterm and Final Term exams.

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- We want to evaluate this long expression using a stack. Let’s try to solve it on paper.
- Here we have five columns ie input, op1, op2, value and stack. We will run ours

pseudocode program. At the beginning we read the input and the result is the number 6. Like 6 - is an operand, so it will be put on the stack. Then we have number 2 which will also

be pushed onto the stack. Now 2 is the newest element. Another element is

PHY101 Short Notes for Final Term and Mid Term

- the number 3, which is also moved to the stack. There are now three elements on it
- stack i.e. 3, 2 and 6. Number 3 is the most recent. For cracking, we’ll get it

first the number 3. The next element is “+”, the operator. Now the second part of ours - the pseudo code is executed. We remove two operands from the stack and use them
- operator (+). The number 3 will be stored in the variable op2 and the number 2 in

PHY101 Short Notes for Final Term and Mid Term

- op1. The (+) operator, i.e. 2+3, is applied to those and the result is stored in a value.
- Now we push the value (ie 5) onto the stack. Now we have two numbers

stack i.e. 5 and 6. Number 5 is the newest element. The next element is “-“. - Since it is also an operator, we pop two elements from the stack, i.e. 5 and 6.
- Now we have 5 in op2 and 6 in op1. When using the operator

#### PHY101 Short Notes for Final Term and Mid Term

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